x^2+x(2+i)+2i=0

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Solution for x^2+x(2+i)+2i=0 equation:


Simplifying
x2 + x(2 + i) + 2i = 0
x2 + (2 * x + i * x) + 2i = 0

Reorder the terms:
x2 + (ix + 2x) + 2i = 0
x2 + (ix + 2x) + 2i = 0

Reorder the terms:
2i + ix + 2x + x2 = 0

Solving
2i + ix + 2x + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2x' to each side of the equation.
2i + ix + 2x + -2x + x2 = 0 + -2x

Combine like terms: 2x + -2x = 0
2i + ix + 0 + x2 = 0 + -2x
2i + ix + x2 = 0 + -2x
Remove the zero:
2i + ix + x2 = -2x

Add '-1x2' to each side of the equation.
2i + ix + x2 + -1x2 = -2x + -1x2

Combine like terms: x2 + -1x2 = 0
2i + ix + 0 = -2x + -1x2
2i + ix = -2x + -1x2

Reorder the terms:
2i + ix + 2x + x2 = -2x + 2x + -1x2 + x2

Combine like terms: -2x + 2x = 0
2i + ix + 2x + x2 = 0 + -1x2 + x2
2i + ix + 2x + x2 = -1x2 + x2

Combine like terms: -1x2 + x2 = 0
2i + ix + 2x + x2 = 0

The solution to this equation could not be determined.

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